4x+[4-2(x+2)]=4x-4

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Solution for 4x+[4-2(x+2)]=4x-4 equation: 


Simplifying
4x + [4 + -2(x + 2)] = 4x + -4

Reorder the terms:
4x + [4 + -2(2 + x)] = 4x + -4
4x + [4 + (2 * -2 + x * -2)] = 4x + -4
4x + [4 + (-4 + -2x)] = 4x + -4

Combine like terms: 4 + -4 = 0
4x + [0 + -2x] = 4x + -4
4x + [-2x] = 4x + -4
4x + [-2x] = 4x + -4

Combine like terms: 4x + [-2x] = 2x
2x = 4x + -4

Reorder the terms:
2x = -4 + 4x

Solving
2x = -4 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
2x + -4x = -4 + 4x + -4x

Combine like terms: 2x + -4x = -2x
-2x = -4 + 4x + -4x

Combine like terms: 4x + -4x = 0
-2x = -4 + 0
-2x = -4

Divide each side by '-2'.
x = 2

Simplifying
x = 2

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